<PRE><B>Question 78860</B>
A plane took 1 hour longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion , what was the flying time for the second part of the trip?
:
Let t = time of the 2nd portion (480 mi)
Then (t+1) = time of the 560 mi portion:
;
The speed is the same on both portions, write an equation from this fact:
s = distance/time
:
560 mi speed = 480 mi speed
{{{560/((t+1))}}} = {{{480/t}}}
:
Cross multiply and you have:
560t = 480(t+1)
560t = 480t + 480
560t - 480t = 480
80t = 480
t = 480/80
t = 6 hrs
:
:
Check solution by finding the speed, which should be the same:
560/7 = 80
480/6 = 80
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