Question 933759
x(x^4+x^2-6)=x^5+x^3-6x
y=some number
z=another number
(x^2+y)(x^2+z)=x^4+x^2-6
x^4+yx^2+zx^2+zy=x^4+x^2-6
yx^2+zx^2+zy=x^2-6
yx^2+zx^2=x^2
y+z=1
yz=-6
if y=3 and z=-2
3*-2=-6
3-2=1
(x^2+3)(x^2-2)=x^4+3x^2-2x^2-6
x((x^2+3)(x^2-2))=x^5+x^3-6x