Question 933723
<pre>
{{{a[2]-a[1]=10-3=7}}}
{{{a[3]-a[2]=17-10=7}}}
{{{a[4]-a[3]=24-17=7}}}

So this is an arithmetic sequence with common difference {{{d=7}}}
and first term {{{a[1]=3}}}

Use the formula for the nth term of an arithmetic sequence:

{{{a[n]=a[1]+(n-1)d}}}

Substitute {{{n=48}}}, {{{a[1]=3}}} and {{{d=7}}}

{{{a[48]=3+(48-1)(7)}}}

{{{a[48]=3+(47)(7)}}}
{{{a[48]=3+329}}}
{{{a[48]=332}}}

Edwin</pre>