Question 933669
Given 2x-6y=12
 Transform the equation into slope intercept form and find the slope and y -intercept of the line.
6y = 2x-12
y = (1/3)x - 2
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slope = (1/3) ; y-intercept = -2
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 and find the equation in slope intercept form of the line that is perpendicular to this line and passes through the point (-1,2).
slope = -3
Form:: y = mx + b
Solve for "b"::
2 = -3*-1 + b
b = -1
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Equation:
y = -3x -1
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Cheers,
Stan H.
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