<PRE><B>Question 79009</B>
In order to combine the fractions we need to find the LCD. The LCD is the common factor that each denominator can multiply to, so in this case the LCD is 


{{{(5x-2)(5x+1)}}}


Notice we can multiply each denominator with the piece that is needed to get to the LCD. So lets multiply each term by the missing piece


{{{((5x+1)/(5x+1))((4x)/(5x-2))-((5x-2)/(5x-2))((2x)/(5x+1))}}} Multiply each fraction by a form of 1 to make the denominators the same


{{{((4x)(5x+1))/((5x+1)(5x-2))-((2x)(5x-2))/((5x+1)(5x-2))}}} Multiply the fractions


{{{(20x^2+4x)/((5x+1)(5x-2))-(10x^2-4x)/((5x+1)(5x-2))}}} Distribute


{{{(20x^2+4x-10x^2+4x)/((5x+1)(5x-2))}}} Combine the numerators


{{{(10x^2+8x)/((5x+1)(5x-2))}}} Combine like terms. This is the simplified answer




</PRE>