Question 78999
Notice this is a sum of cubes if you let A=x and B=3 to get

{{{A^3+B^3=(A+B)(A^2-AB+B^2)}}}


So we get


{{{x^3+3^3=(x+3)(x^2-3x+3^2)}}}


Which simplifies to:


{{{x^3+3^3=(x+3)(x^2-3x+9)}}}