Question 933635
{{{(1+2i)/(3-4i)+(2-i)/5i}}}


{{{(1+2i)5i/5i(3-4i)+((2-i)(3-4i))/(5i(3-4i))}}}


{{{(5i-10)/(15i+20)+(2-11i)/(15i+20)}}}...common denominator is {{{(15i+20)}}}, so add numerators


{{{(5i-10+2-11i)/(15i+20)}}}


{{{(-8-6i)/(15i+20)}}}....multiply both by {{{(15i-20))}}} to eliminate {{{i}}} from denominator


{{{((-8-6i)(15i-20))/((15i+20)(15i-20))}}}


{{{(-120i+160-90i^2+120i)/((15i)^2-20^2))}}}


{{{(160-90(-1))/((15i)^2-20^2))}}}


{{{250/(-225-400))}}}


{{{250/(-625))}}}........divide both by {{{125}}}


{{{-cross(250)2/cross(625)5)}}}


{{{-2/5)}}}