Question 933565
The perimeter of a rectangular garden is 324ft. If it's length is twice it's width.

A. Write an equation for the perimeter of the garden.

Perimeter = 2(l+w)
2(l+w)=324

but l=2w

2(2w+w)=324
2*3w=324
6w=324
B. Write the equation for the relation of the length and the width
l=2w
C. What are the dimension of the garden.

6w=324
/6
w=54
l=2w=108

D. Prove that  the area of the garden is 5,832 square ft.

Area = l*w

A= 54*108
A= 5,832 sq.ft