Question 933555
x^4-mx^3-2x^2+(3m-5)x+m by (x-m) gives a remainder of 5.

substitute x=m

m^4-m^4-2m^2+3m^2-5m+m 

m^2-4m =5

m^2-4m-5=0

m^2--5m+m-5=0

m(m-5)+1(m-5)=0

(m-5)(m+1)=0
m=5 OR 1