Question 933537
1. How to solve (-i)^-3.
(-i)^-3=1/-i^3=1/-(-i^3)=1/i

2. Solve ( 1 + 1/i)^4
(1+1/i)^4=(1+1/i)^2*(1+1/i)^2
=(1+2/i+1/i^2)^2*(1+2/i+1/i^2)^2
=(1+2/i-1)^2*(1+2/i-1)^2
=(2/i)^2*(2/i)^2
=4/i^2*4/i^2=4/-1*4/-1=16