Question 933522
Volume of the sphere material is the difference between the outer sphere and the inner sphere, and then you need the material density, D.


Height MUST be diameter, so the outer radius is {{{(230-2*6)/2=109*mm}}}.  With that, your given internal radius of 2700 millimeters is nonsense.


ANOTHER INTERPRETATION:
The height 230 millimeters is not important because it only is a datum about sphere position.  The volume of the sphere material would be {{{(4/3)*pi*2706^3-(4/3)*pi*2700^3=((4*pi)/3)(2706^3-2700^3)*mm^3}}}.


If you have some known material density of D  grams per cubic millimeter, then you would have a "weight"  (not really, because it be MASS) of {{{highlight(((4pi)/3)(2706^3-2700^3)*D)}}}  grams.