Question 933518
---	percent	----------------	Amount									
acid type I	10	----------------			380	ml						
acid type II	18	----------------			x	ml						
Mixture	15	----------------	380	+	x	ml						
												
10	*	380	+	18	x	=	15	(	380	+	x	)
3800	+	18	x	=	5700	+	15	x				
18	x		-15	x	=	-3800	+	5700				
3	x	=	1900									
/	3											
x	=	633.33		ml	acid type II							
												
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