Question 933440
Find equation for hyperbola that has foci (0, +-5) and vertices (0, +-3)
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hyperbola has a vertical transverse axis
Its standard form of equation: {{{(x-h)^2/a^2-(y-k)^2/b^2=1}}},(h,k)=coordinates of center
For given hyperbola:
center: (0,0)
vertices:
a=3
a^2=9
foci:
c=5
c^2=25
c^2=a^2+b^2
b^2=c^2-a^2=25-9=16 
equation: {{{x^2/9-y^2/16=1}}}