Question 933427
The equation is in quadratic form.  First solve for {{{x^2}}}.  Can you factor  {{{9u^2-25u+16}}}?


{{{u=(25+- sqrt(25^2-4(9*16)))/(2*9)}}}
{{{u=(25+- 7)/18}}}
{{{u=1}}}  or {{{u=32/18=16/9}}}
You want the square root of each of them.


x=-1, or x=1, or x=-4/3, or x=4/3