Question 933276
Not sure what you really mean:
(1/3)(ln(a)-4*ln(b))-ln(c)
{{{(1/3)(ln(a)-4*ln(b))-ln(c)}}}



{{{ln(a^(1/3))-ln(b^(4/3))-ln(c)}}}



{{{ln((a^(1/3))/(b^(4/3)))-ln(c)}}}



{{{ln((a^(1/3))/((b^(4/3))(c)))}}}


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