Question 933208
What does a graph of an ellipse with vertices (-2,6) and (-2,16); focus (-2,14) look like? State center, co-vertices, and foci. 
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Given ellipse has a vertical major axis.
Its standard form of equation:{{{(x-h)^2/b^2+(y-k)^2/a^2=1}}}, a>b,(h,k)=coordinates of center
For given ellipse:
x-coordinate of center=-2
y-coordinate of center=11 (midpoint of y=6 and y=16 on the vertical major axis
center(-2,11)
a=5 (distance from center to vertices)
a^2=25
c=3
c^2=9
c^2=a^2-b^2
b^2=a^2-3^2=25-9=16
equation:{{{(x+2)^2/16+(y-11)^2/25=1}}}
see graph below:
y=(25(1-(x+2)^2/16))^.5-11
{{{ graph( 400, 400, -20, 20, -20, 20,(25(1-(x+2)^2/16))^.5-11,-(25(1-(x+2)^2/16))^.5-11) }}}