Question 933151
{{{sqrt(20x^3y^6z^9)}}}.............write {{{x^3}}} as {{{x^2*x}}}, {{{y^6}}} as {{{y^2*y^2*y^2}}},{{{z^9}}} as {{{z^2*z^2*z^2*z^2*z}}}, and {{{20}}} as {{{2^2*5}}}


{{{sqrt(2^2*5x^2*x*y^2*y^2*y^2*z^2*z^2*z^2*z^2*z)}}}.......{{{sqrt(2^2)=2}}}, same apply to the other variables 

{{{2x*y*y*y*z*z*z*z*sqrt(5xz)}}}

{{{2x*y^3*z^4*sqrt(5xz)}}}


you have an answer:
{{{2x^2y^2z^3*sqrt(5xy^3z^3)}}} and the part {{{sqrt(5xy^3z^3)}}} is not completely simplified; it has {{{sqrt(y^3)=sqrt(y^2*y)}}} which is {{{y*sqrt(y)}}} and {{{sqrt(z^3)}}} which is {{{z*sqrt(z)}}}


so, your answer is: {{{highlight(2x*y^3*z^4*sqrt(5xz))}}}