<PRE><B>Question 932392</B>
Let a&lt;sub&gt;1&lt;/sub&gt;= the first number
    a&lt;sub&gt;2&lt;/sub&gt;= the second number
                d= 1 
The sum of two consecutive numbers is 73.
Sn = n/2(2a&lt;sub&gt;1&lt;/sub&gt;+(n-1)d)
73 = 2/2(2a&lt;sub&gt;1&lt;/sub&gt;+(2-1)1)
73 = 2a&lt;sub&gt;1&lt;/sub&gt;+1
72 = 2a&lt;sub&gt;1&lt;/sub&gt;
36 = a&lt;sub&gt;1&lt;/sub&gt;
a&lt;sub&gt;2&lt;/sub&gt; = a&lt;sub&gt;1&lt;/sub&gt;+(n-1)d
a&lt;sub&gt;2&lt;/sub&gt; = 36+(2-1)1
a&lt;sub&gt;2&lt;/sub&gt; = 36+1
a&lt;sub&gt;2&lt;/sub&gt; = 37

The numbers are 36 and 37.


</PRE>