Question 78890
For the triangular sides, the area of one side is:
{{{A = (1/2)bh}}} The base (b) is given as 10 feet and the height (h) is given as 10 feet. So...
{{{A = (1/2)(10)(10)}}}
{{{A = 50}}} square feet for one of the four triangular sides.
The four sides would have an area that is four times this or 4 X 50 = 200 square feet.
For the base,the area would be:
{{{A = L*W}}} The length (L) and width (W) are given as 10 feet each, so...
{{{A = (10)(10)}}}
{{{A = 100}}}square feet.
The total area is the sum of all of these:
{{{A[t] = 200+100}}}
{{{A[t] = 300}}}square feet.