Question 932843
Half-life for HALF the quantity of the original quantity.


{{{1/2=1*(0.98)^t}}}


What base do you want to use?  Common logs for base 10?


{{{log(10(1/2))=t*log(10,0.98)}}}


{{{t=log(10,(1/2))/log(10,0.98)}}}


{{{t=0.30103/0.00877}}}


{{{highlight_green(t=34.34)}}} years.



A quick check (?),
{{{50=100*(0.98)^34.3}}}  ?
Okay!