Question 932634
This is mostly many algebra steps, relying on substitution.   Best start is to solve the second equation for y in terms of x, and substitute this into the first equation.  Solve for the value of x, first.  This should be a long process, but not too complicated.


{{{y=1/2-x^2/2-x}}}
;
{{{(x-3)^2+y^2-4y+4=25}}}, and do the substitution.  You might do the squaring of y separately and then include this for {{{y^2}}} in the equation...