Question 932622
{{{(x-2)^2+(y-3)^2=25}}}
{{{ (y-3)^2=25 - (x-2)^2}}}
..........
{{{(y-3)^2+(x+2)^2=9}}}
25 - (x-2)^2 + (x+2)^2 = 9
25 - x^2 + 4x - 4 + x^2 + 4x + 4 = 9
8x = -16
x = -2  and y = 0, 6 {{{(y-3)^2 = 9}}}, y = 3 ± 3
(-2,0)  and (-2,6) the points of Intersection
.......
{{{drawing(300,300,    -10,10,-10,10,  arc(2,3,10,10), arc(-2,3,6,6),   
 grid(1),
circle(-2, 6,0.4),
circle(-2,0,0.4),
graph( 300, 300, -10,10,-10,10,0))}}}