Question 932636
{{{x^2+y^2-10x+6y=47}}}
Complete the square in x and y.
{{{x^2-10x+y^2+6y=47}}}
{{{(x^2-10x+25)+(y^2+6y+9)=47+25+9}}}
{{{(x-5)^2+(y+3)^2=81}}}
It's a circle centered at ({{{5}}},{{{-3}}}) with a radius of {{{9}}}.