Question 932586
I think I'm mixing something up in the question below. 
Write the general form of the equation of the circle with radius r and center (h,k).
 r= 2 sqrt( 3 ) (h, k) = (4, -4) 
This is what I came up with 
(x-4)^2 + (y + 4)^2 = (2sqrt(3))^2
(x-4)^2 + (y+4)^2 = 12
Comment:: 
I think either of the 2 equations above is the answer
the problem is looking for.
Cheers,
Stan H.
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The rest of this does not give the "general form".
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which gives 
x^2-8x+16 + y^2+8y+16 = 12

then 
x^2+y^2-8x+8y+32=12 
then I get confused after I subtract 32 from both sides 
x^2+y^2-8x+8y = -20
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Cheers,
Stan H.