Question 932319
mean of 35 and a standard deviation of 6.  {{{z = blue(x - 35)/blue(6)}}}  
.....
 Using a TI calculator 0r similarly a Casio fx-115 ES plus
P( 28 <x< 38) = P(-7/6 < z < 3/6)= normalcdf(-7/6, 1/2)= .5698
P(41 < x < 44) = P( 6/6 < z < 9/6)= normalcdf(1, 1.5)= .0918
.......
65th percentile:  6(invNorm(.65)) + 35 = 6( .3853) + 35 = x = 38 (using next Integer)
90th percentile:  6(invNorm(.90)) + 35 = 6 (1.2816) + 35 = x