Question 932479
{{{sin(theta)=cos(theta)=0 +- sqrt(2)/2}}}
{{{sin^4(theta)=cos^4(theta)=(sqrt(2)/2)^4=4/16=1/4}}}
So,
{{{sin^4(theta)+cos^4(theta)=1/4+1/4}}}
{{{sin^4(theta)+cos^4(theta)=1/2}}}