Question 925242
Let x = the amount invested at 12%
    y = the amount invested at 8%

$5900 is invested.
x+y=5900

part of it at 12% and part of it at 8%.  For a certain year, the total yield is $596.
.12x+.08y=596
.12x(-12.5)+.08y(-12.5)=596(-12.5)
-1.5x- y=-7450

    x+ y= 5900
-1.5x- y=-7450
    -.5x=-1550
       x= 3100

Substitute x with $3100
$3100+y=5900
      y=5900-3100
      y=2800

Out of $5900, $3100 was invested at 12% and $2800 was invested at 8%.

Check
.12(3100)+.08(2800)=596
     372 +     224 =596
               596 =596