<PRE><B>Question 930703</B>
Let a = the first side
    b = the second side
    c = the third side

A triangle has a perimeter of 46 meters.
a + b + c = 46 meters

The first side of the triangle is four meters longer than the second side.
a=b+4

The third side is 10 meters shorter than double the second side.
c=2b-10

Substitute a with b+4 and c with 2b-10
(b+4) + b + (2b-10) = 46
              4b-6  = 40
                4b  = 46+6 
                4b  = 52
                 b  = 13 meters

Substitute b with 13
a = 13 + 4
a = 17 meters

c = 2(13)-10
c = 26-10
c = 16

The length of each side of the triangle are 17, 13 and 16 meters.

Check
17 + 13 + 16 = 46
          46 = 46
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