Question 932191
r = w/t
t = w/r
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x = rate of newer pump
y = rate of older pump = 1/( 2(1/x) )
y = rate of older pump = 1/( 2/x )
y = rate of older pump = x/2
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time of newer pump = 1/x
time of older pump = 1/y
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rate together:
x + y = 1/4
x + x/2 = 1/4
(2/2)x + (1/2)x = 1/4
(3/2)x = 1/4
x = (1/4)/(3/2)
x = (1/4)*(2/3)
x = (1/2)*(1/3)
x = 1/6
y = x/2
y = (1/6)/2
y = 1/12
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answer:
time of newer pump = 6 hours
time of older pump = 12 hours
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