Question 78902
I really think it is wrong to submit a question without any words

The answer is (6ab^2/35b) (42a/18ab)

Is that OK?

Oh, you want me to simplify it?

Why didn't you say so?

So in the first term which is (6ab^2/35b) i see that b can be canceled since the same factor b is in the top and the bottom

6ab/35

In the secont term which is 42a/18ab I see a can be canceled since the factor a is in the numerator and denominator.  Also 42 and 18 are divisible by 6 

7/3b

So we are multiplying (6ab/35) * (7/3b)

The basic idea in this kid of problem is: (A/B)*(C/D) is just (A*C)/(B*D)

so that is (42ab / 105 b)

This can be condensed some more by canceling 7 from top and bottom, and b

I end up with 2a / 5

There is not really a way to check this kind of problem except to do it over again, preferably by antoher person doing the operations in a different order

(6ab^2/35b) (42a/18ab)

2*3*2*3*7*a*a*b*b / 5*7*b*2*3*3*a*b 

cancel out most of that

This time I also get 2 a / 5 which luckily confirms the first response (I had to change them each three times to make this work)