<PRE><B>Question 931937</B>
I&#39;m going to assume the original function is *[Tex \Large f(x)= \frac{8x-1}{5}]



The idea is to replace f(x) with y, swap x and y, and then solve for y like so...



*[Tex \Large f(x)= \frac{8x-1}{5}]



*[Tex \Large y = \frac{8x-1}{5}]



*[Tex \Large x = \frac{8y-1}{5}]



*[Tex \Large 5x = 8y-1]



*[Tex \Large 5x+1 = 8y]



*[Tex \Large 8y = 5x+1]



*[Tex \Large y = \frac{5x+1}{8}]



So the inverse function is *[Tex \Large f^{-1}(x) = \frac{5x+1}{8}]
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