Question 931861
log5 (8x+8y) = log5 8(x+y)  = log5 (8)  + log5 (x+y)
 log7(13m/s) = log7(13m) - log7(s)
...........
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]***
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]***
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]