Question 931785
mean of 66 and a standard deviation of 4.
n = 48,  {{{z =blue (x - 68)/blue(4/sqrt(48)) =blue (x - 68)/blue(.58) }}}
P(x < 65) = P(z <-1/.58) = normalcdf(-100, -1.72)
P(65 < x <67) = P(-1.72 < z < 1.72) = normalcdf(-1.72, 1.72)
P( 67< x < 68) = P(1.72 < z < 3.45)=normalcdf(1.72, 3.45)
P(x > 68) = P(z > 3.45) = normalcdf(3.45, 100)