Question 931664
Previously Posted
4x^2+y^2=64
<u>-1(x^2+y^2=52)</u>
3x^2 = 12
x^2 = 4 
x = ± 2
y = &#8730;48 = ±4&#8730;3 {{{y^2 = 52-4}}}
.......
(-2,4&#8730;3),  (-2,-4&#8730;3),  (2,4&#8730;3), (2,-4&#8730;3),  

{{{drawing(300,300,   -10,10,-10,10,  arc(0,0,8,16),  
 grid(1),
circle(0, 0,sqrt(52)),
graph( 300, 300, -10,10,-10,10,0))}}}