Question 931572
Previously Posted
2y-x=2   0r x = {{{2y-2}}} All started here  with typo
.....
x^2-4y^2=16
(2y-2)^2 - 4y^2 = 16
4y^2 - 8y + 4 - 4y^2 = 16
-8y + 4 = 16
-8y = 12
y = -12/8 = -3/2
x = -5 {{{2(-3/2)- 2}}}
(-5, -1.5) the solution set for this System
{{{drawing(300,300,   -6, 6, -6, 6, grid(1), 
graph( 300, 300, -6, 6, -6, 6,0,.5x + 1, .5sqrt(x^2 - 16), -.5sqrt(x^2 - 16)  ))}}}