Question 931388


lot with perimeter of {{{P=86m}}} 

if the length {{{L}}} is {{{7m}}} more than the width {{{W}}}, then we have

{{{L=W+7m}}}

{{{P=2L+2W}}} ...plug in given values

{{{86m=2(W+7m)+2W}}}...solve for {{{W}}}

{{{86m=2W+14m+2W}}}

{{{86m-14m=4W}}}

{{{72m=4W}}}

{{{72m/4=W}}}

{{{highlight(W=18m)}}}

now find the length

{{{L=18m+7m}}}

{{{highlight(L=25m)}}}