Question 931112


sqrt of twice a number= {{{sqrt(2x)}}}

{{{x- sqrt(2x)=4}}}


{{{x-4= sqrt(2x)}}}

square on both sides

(x-4)^2 =2x

x^2-8x+16=2x

x^2-10x+16=0

x^2-8x-2x+16=0

x(x-8)-2(x-8)=0
(x-8)(x-2)=0
x= 2 OR 8