Question 931108


how to factor 

{{{(5n^2 +3)(n-2)}}} ....this is factored already; multiply to see where we got it from

{{{5n^3-10n^2+3n-6 }}}...if we group terms

{{{(5n^3-10n^2)+(3n-6) }}} and factor out {{{5n^2}}} from first group and {{{3}}} from second group, we get

{{{5n^2(n-2)+3(n-2) }}} and

{{{(5n^2+3)(n-2) }}} we got same as at very beginning