Question 930971
x = speed of plane
y = speed of car
x = 3y
t = time traveled by car
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s = d/t
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speed of plane:
x = 960/(t - 8)
3y = 960/(t - 8)
y = 960/3(t - 8)
y = 320/(t - 8)
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speed of car:
y = 960/t
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equate speeds:
320/(t - 8) = 960/t
320/(t - 8) - 960/t = 0
320t/t(t - 8) - 960(t - 8)/t(t - 8) = 0
320t - 960(t - 8) = 0*t(t - 8)
320t - 960t + 8*960 = 0
-640t + 7680 = 0
t = 7680/640
t = 12
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x = 960/(t - 8)
x = 960/(12 - 8)
x = 240
y = 320/(t - 8)
y = 320/(12 - 8)
y = 80
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answer:
x = speed of plane = 240 kph
y = speed of car = 80 kph
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