Question 930952
9x^2-6x= 18y-19
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completing the Square: 9x^2 - 6x + 0 (Format: ax^2 + bx + c)
-(-6/2*9) = 6/18 = 1/3
9(x - 1/3)^2 = 18y + -19 + 1 = 18y - 18
18y - 18 = 9(x-1/3)^2
y = (1/2)(x-1/3)^2 + 1
V(1/3,1)
1/(4p) = 1/2,   p = 1/2
F(1/3, 3/2)
Directrix:  y = 1/2  {{{1-1/2}}}
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the vertex form of a Parabola opening up(a>0) or down(a<0), 
{{{y=a(x-h)^2 +k}}} 
where(h,k) is the vertex  and  x = h  is the Line of Symmetry , 
the focus is (h,k + p), With Directrix y = (k - p), a = 1/(4p)