Question 930541

a jet plane travelling at 500 mph over takes a propeller plane travelling at 200 mph that had a 2-hour head start.how far the starting point are the planes?
<pre><font face = "Tohoma" size = 4 color = "indigo"><b>Upon overtaking the propeller plane, the jet and propeller planes would’ve traveled the same distance
Let the distance traveled by both planes, to the meeting point, be D
Then time taken by propeller plane to travel to planes’ meeting point = {{{D/200}}}
Time taken by jet plane to travel to planes’ meeting point = {{{D/500}}}
We therefore have: {{{D/200 = D/500 + 2}}}
5D = 2D + 2,000 ------- Multiplying by LCD, 1,000
5D – 2D = 2,000
3D = 2,000
D, or distance traveled by the planes, or distance from starting point = {{{2000/3}}}, or {{{highlight_green(666&2/3)}}} miles
You can do the check!! 
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</font face = "Tohoma" size = 4 color = "indigo"></b>Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
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