Question 930532
f(t) = 2 - 3t²


A.) f(-2)
= 2 - 3(-2)² {substituted -2 for t}
= 2 - 3(4) {evaluated exponent}
= 2 - 12 {multiplied}
= -10 {subtracted}


B.) f(-t)
= 2 - 3(-t)² {substituted -t for t}
= 2 - 3t² {evaluated exponent}


C.) -f(t)
= -(2 - 3t²) {took negative of entire right side}
= -2 + 3t² {distributed negative sign}


D.) -f(-t)
f(-t) was 2 - 3t² {see problem B.}
= -(2 - 3t²) {took negative of entire right side}
= -2 + 3t²
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