Question 930396
Find the values of the trigonometric functions of θ if csc θ = 13/9

and θ is in Quadrant II
 

sin (θ) =   
cos (θ) =   
tan (θ) =   
cot (θ) =   
sec (θ) =

Please explain, I know that sin must be 9/13?
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cos = sqrt(1 - sin^2) = sqrt(1 - 81/169) = sqrt(88/169)
cos = {{{-2sqrt(22)/13}}} (Q2 --> negative)
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tan = sin/cos
cot = 1/tan
sec = 1/cos