Question 930373
x = pounds of peanuts
y = pounds of fruit
z = pounds of cashews
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"one ingredient must have twice the weight of other two" ...
arbitrarily choose the weight of peanuts to be twice the sum of the weights of fruit and cashews:
x = 2(y + z)
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sum of weights:
x + y + z = 140
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sum of costs:
3x + 6y + 3z = 6*140
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put the system of linear equations into standard form
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x = 2y + 2z
x + y + z = 140
3x + 6y + 3z = 840
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x - 2y - 2z = 0
x + y + z = 140
3x + 6y + 3z = 840
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = pounds of peanuts = 93.333333
y = pounds of fruit = 140
z = pounds of cashews = -93.333333
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as you can see, pounds of cashews comes out negative, which is impossible in real life.
this means that the problem statement is fundamentally incorrect.
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