Question 930320
y = kx
2 = 3k
2/3 = k
y = (2/3)x , {{{x = 6}}}, y = 4
.........
y = kx
-16 = 6k
-16/6 = k = -8/3
y = (-8/3)x,  {{{y = 8}}} ,   (-3/8)(8) = x = -3