Question 930319
Use the common denominator, {{{x^2-y^2=(x+y)(x-y)}}}
{{{4x/(x^2-y^2)+3/(x+y)-2/(x-y)=4x/(x^2-y^2)+(3(x-y))/((x+y)(x-y))-(2(x+y))/((x+y)(x-y))}}}
{{{4x/(x^2-y^2)+3/(x+y)-2/(x-y)=(4x+3(x-y)-2(x+y))/((x+y)(x-y))}}}
{{{4x/(x^2-y^2)+3/(x+y)-2/(x-y)=(4x+3x-3y-2x-2y))/((x+y)(x-y))}}}
{{{4x/(x^2-y^2)+3/(x+y)-2/(x-y)=(5x-5y)/((x+y)(x-y))}}}
{{{4x/(x^2-y^2)+3/(x+y)-2/(x-y)=(5(x-y))/((x+y)(x-y))}}}
{{{4x/(x^2-y^2)+3/(x+y)-2/(x-y)=highlight(5/(x+y))}}}