Question 930317
<pre>
{{{ln((x^4)sqrt(x^2+1))}}}

Use the rule {{{ln(AB)=ln(A)+ln(B)}}}

{{{ln(x^4)}}}{{{""+""}}}{{{ln(sqrt(x^2+1)))}}}

Write the square root as the {{{1/2}}} power

{{{matrix(2,3,"", "", "",

ln(x^4),""+"",ln((x^2+1)^(1/2))   )}}}

Use the rule {{{ln(A^B)=B*ln(A)}}} on both terms

{{{4ln(x)}}}{{{""+""}}}{{{expr(1/2)ln(x^2+1)}}}.

[Comment: All logarithms have bases.  It's just that when you see
"log" without a written the base is understood to be 10 and when
you see "ln" without a written base, the base is understood to be
e = 2.718....]

Edwin</pre>