Question 78739
This problem is asking you to find the hypoteneuse of a
right triangle with the 2 other sides given.
To solve this, use the pythagorean theorem:
{{{a^2+b^2=c^2}}} where c is the hypotenuese while
a and b are the other 2 sides.
So, for your problem,
{{{c^2=32^2+32^2}}}
{{{c^2=1024+1024}}}
{{{c^2=2048}}}
Solve for c by taking the square root of both sides:
{{{c=sqrt(2048)}}}
{{{c=32*sqrt(2)}}}

There is also a trick to problems like this. If you recognize that
the triangle is an isosceles right triangle (i.e. two sides are equal),
then the hypoteneuse is always {{{s*sqrt(2)}}} where s is one side.

Good Luck
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