Question 930182
Change the expression tan^2(beta)-sin^2(beta) all over tan^2(beta) to an equivalent expression involving only sines and cosines
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{{{(tan^2(beta)-sin^2(beta))/tan^2(beta)}}}
{{{(sin^2(beta)/cos^2(beta)-sin^2(beta))/(sin^2(beta)/cos^2(beta))}}}
{{{(sin^2(beta)-cos^2(beta)sin^2(beta))/(sin^2(beta))}}}
{{{(sin^2(beta))(1-cos^2(beta))/(sin^2(beta))=sin^2(beta)}}}