Question 930211
Please help me solve this: {{{ find f^-1  }}}   {{{ f(x)=(x+2)^2  }}}  x is greater than or equal to -2
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Note: y = (x+2)^2 is a parabola opening upward from vertex = (-2,0)
That function does not have an inverse as each x-value would have 
2 corresponding y-values.
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But, if x >= -2, the function DOES have an inverse.
1st: Interchange x and y to get:
x = (y+2)^2
2nd: Solve for "y"::
y+2 = sqrt(x)
f^=1 = sqrt(x)-2 and y >= -2
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Cheers,
Stan H.
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